Question

Mr. lance keeps a jar of candy on his desk for students to pick from when they do well on a test. the jar contains 5 snickers, 2 butterfingers, 4 almond joys and 3 milky ways. if two students get to pick candy from the jar, what is the probability that the first student picks a snickers and then the second student also picks a snickers?

Answer 1

there are 5 snickers ...and a total of 14 candy bars

probability of first kid getting a snickers = 5/14
probability of 2nd kid getting a snickers = 4/13

probability of both = 5/14 * 4/13 = 20/182 reduces to 10/91

Answer 2

Answer:
`(10)/(91)`

Explanation:

Given : The jar contains 5 snickers, 2 butterfingers, 4 almond joys and 3 milky ways.

Total candies in the jar = 5+2+4+3=14

Probability of drawing first candy a snickers =
`P(S_1)=(5)/(14)`

After this, number of candies left in the jar = 14-1=13

Number of snickers left = 5-1=4

Then the conditional probability of getting another snickers =
`P(S_2|S_1)(4)/(13)`

We know that
`P(A\cap B)=P(B|A)* P(A)`

Thus,
`P(S_1\cap S_2)=P(S_2|S_1)* P(S_1)`

`=(4)/(13)*(5)/(14)=(10)/(91)`

Hence, the probability that the first student picks a snickers and then the second student also picks a snickers
`=(10)/(91)`