Apply the compound interest formula:
A = P (1+ r/n)^nt
Where:
A = Value of the investment after interests
P = principal investment
r= interest rate (in decimal form ) =5.5/100 = 0.055
t= years
n= number of compounding periods in each year
Replacing:
A = 10,000 (1+0.055/n)^5n
• a) n=2
A = 10,000 (1+0.055/2)^(5x2)
A = 10,000( 1+0.0275)^10
A = 10,000 ( 1.0275)^10
A = $13,116.5
• b) n=4
A = 10,000 (1+0.055/4)^(5x4)
A = 10,000 (1.01375)^20
A = $13,140.66
• C) n=12
A = 10,000 (1+0.055/12)^(5x12)
A = 10,000 (1.004583333)^60
A= $13,157.03
• d) for compounded continuously apply:
,
•
A = P x e ^(rt)
where
e ≅2.7183
A = 10,000 x 2.7183 (0.055 x5) = $13,165.33