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Solve the system by substitution.
-x-y-z=-8
-4x+4y+5z=7
2x+2z=4

User Adavo
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1 Answer

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1. x=−y+8−z 2.x=−​7−4y−5z (everything over 4) ​​ 3.x=2−z 1.y=-x+8-z 1.z=-x+4-y 2.y=7+4x-5x (everything over 4) 2.z=7+4x-4y (everything over 5) 3.z=2-x
User Rischan
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