Question

The image shows a geometric representation of the function f(x) = x2 – 2x – 6 written in standard form.

What is this function written in vertex form?


f(x) = (x –1)2 – 7

f(x) = (x +1)2 – 7

f(x) = (x –1)2 – 5

f(x) = (x +1)2 – 5

Answer 1

First one

Explanation:

Answer 2

we know that

To find the equation in vertex form, we need to factor the function

so

`f(x) = x^(2) - 2x - 6`

Complete the square. Remember to balance the equation

`f(x) = x^(2) - 2x +1-1- 6`

`f(x) = x^(2) - 2x +1-7`

Rewrite as perfect squares

`f(x) = (x-1)^(2) -7`

in this problem

the vertex is the point
`(1,-7)`

therefore

the answer is

The function written in vertex form is equal to
`f(x) = (x-1)^(2) -7`