Question

What is the velocity of a freely falling object 6 seconds after being dropped? After 10 seconds?

Answer 1

The speed of an object under free fall that starts at rest can be found using the formula:

`v=gt`

Where g is the gravitational acceleration:

`g=9.8(m)/(s^2)`

Remember that the velocity is a vector quantity. While the speed can be found using the given formula, a free falling object that starts at rest will get a velocity directed to the downward direction.

Substitute the value of g and the different values of t (6 seconds and 10 seconds) to find the velocity of the object at those moments:

`v_1=(9.8(m)/(s^2))(6s)=58.8(m)/(s)`
`v_2=(9.8(m)/(s^2))(10s)=98(m)/(s)`

Therefore, the velocity of a freely falling object 6 seconds after being dropped is 58.8m/s downwards.

The velocity of a freely falling object 10 seconds after being dropped is 98m/s downwards.