A quadratic equation may be expressed in vertex form as:
y = a(x - h)² + k, the vertex being (-h , k)
For option A, the vertices are visibly different. (-4 , 0) and (4 , 0)
For B, the graphs' vertices are the same, (0 , 0).
For C, the vertices (can be obtained by differentiating and putting equal to 0) are (0 , -4) and (0 , 4)
For D, the vertices are (4 , 0) and (0 , 4)
Thus, the answer is B.