Question

An object is dropped from a small plane. As the object falls, its distance, d, above the ground after t seconds, is given by the formula d = –16t2 + 1,000. Use an inequatily equation to find for the interval of time taken by the object to reach the height greater than 300 feet above the ground

Answer 1

find where it equals 300
300=-16t²+1000
minus 1000 from both sides
-700=-16t²
divide both sides by -16
43.75=t²
square root both sides
6.614=t

it took at 6.614 seconds to get to a height of 300 ft above the ground

Answer 2

-16t^2 + 1000 > 300
16t^2 < 1000 - 300
16t^2 < 700
t^2 < 700/16
t^2 < 43.75
t < 6.61