Factor completely x^4 +8x^2 -9

asked Jul 16, 2015 85.9k views

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Factor completely
x^4 +8x^2 -9

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$x^4 +8x^2 -9=\\ x^4-x^2+9x^2-9=\\ x^2(x^2-1)+9(x^2-1)=\\ (x^2+9)(x^2-1)=\\ (x^2+9)(x-1)(x+1)$

Jicking answered Jul 23, 2015

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