We are asked to determine the spring constant given that it is stretched a distance of 0.391 meters and there is a restoring force of 0.922 Newtons.
To do that we will use Hooke's law:
Where:
![\begin{gathered} F=\text{ restoring force} \\ k=\text{ spring constant} \\ x=\text{ deformation} \end{gathered}]()
Now, we solve for the spring constant by dividing both sides by "-x":
now, we plug in the values:
Now, we solve the operations:
Therefore, the spring constant is 2.36 Newtons.