Question

P^2-4p-32/p+4

A. –p + 8; p ≠ –4
B. p – 8; p ≠ –4
C. –p – 8; p ≠ –4
D. p + 8; p ≠ –4

Answer 1

p^2-4p-32=(p-8)(p+4)


`(p^2-4p-32)/(p+4)= ((p-8)(p+4))/(p+4)=p-8`
and p must not be equal to -4


B is answer

Answer 2

The answer is B. p – 8; p ≠ –4

The expression is:
`( p^(2)-4p-32)/(p+4)`
Since the the divisor cannot be zero, that means that p+4 cannot be zero:
p + 4 ≠ 0
⇒ p ≠ -4

Let's simplify this expression:

`( p^(2)-4p-32)/(p+4) = ( (p+4)(p-8))/(p+4)`

Now, cancel out (p+4) and you will get:

`( (p+4)(p-8))/(p+4) = p-8`