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8 men and 6 women arrive separately in a random fashion to a meeting. What is the probability that the first 4 people to show up are men?

User Neigaard
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1 Answer

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The answer is 10/143.

The probability that the first person is a man is 8/14 (because there are 8 men among 14 people).
The probability that the second person is also a man is 7/13 (because there are 7 men (one has already arrived) among 13 people (because one has already arrived).
The probability that the third person is also a man is 6/12.
The probability that the fourth person is also a man is 5/11.

Because all these events occur together, we will use the multiplication rule and multiply the probabilities.
Thus, the probability that the first 4 people to show up are men is:

(8)/(14) * (7)/(13) * (6)/(12) * (5)/(11) = (8*7*6*5)/(14*13*12*11) = (1680)/(24024) = (168*10)/(168*143) = (10)/(143)
User Marvelous
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