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What is the oxidation number of tin (Sn) in the compound Na2SnO2? A. -2 B. 0 C. +2 D. +3

User BurninLeo
by
8.2k points

2 Answers

2 votes

O.N. of Na = +1

O.N. of O = -2

Let, O.N. of Tin = x

1*2 + x + -2*2 = 0

2+x-4 = 0

x-2 = 0

x = 2

SO OPTION C IS YOUR ANSWER......

User Eyedfox
by
8.5k points
4 votes

Answer: Option (C) is the correct answer.

Step-by-step explanation:

It is known that oxidation number of sodium is +1 and the oxidation number of oxygen is -2.

Let the oxidation number of tin (Sn) is x.

Therefore, calculate the oxidation number of tin in the given formula as follows.


Na_(2)SnO_(2)

= (2 \times oxidation number of Na) + Oxidation number of Sn + (2 \times oxidation number of O)

=
(2 * +1) + x + (2 * (-2))

So, 2 + x - 4 = 0

therefore, x = +2

Thus, we can conclude that the oxidation number of tin (Sn) in the compound
Na_(2)SnO_(2) is +2.

User Adrien Zier
by
8.3k points
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