Question

Two factory plants are making TV panels. Yesterday, Plant A produced 8000 panels. One percent of the panels from Plant A and 4% of the panels from Plant B were defective. How many panels did Plant B produce, if the overall percentage of defective panels from the two plants was 3% ?

Answer 1

To find the number of panels produced by Plant B, we need to solve an equation using the information provided in the question.

Step-by-step explanation:

To find the number of panels produced by Plant B, we need to first find the number of defective panels produced by Plant A and Plant B separately.

Number of defective panels from Plant A = 1% of 8000 = 0.01 * 8000 = 80

Let the number of panels produced by Plant B be x. Number of defective panels from Plant B = 4% of x = 0.04 * x

According to the question, the overall percentage of defective panels from the two plants is 3%. So, (80 + 0.04 * x)/(8000 + x) = 0.03

Solving the equation, we can find the value of x, which represents the number of panels produced by Plant B.

Answer 2

8000 from plant A with 1% defective
x from plant B with 4% defective
8000 + x = y with 3% defective

da/a = 0.01 -> 80 = da
db/b = 0.04 -> db = 0.04b
(da+db)/(a+b) = 0.03

(80+b*0.04)/(8000+b) = 0.03
80+b*0.04 = 0.03*(8000+b)
80+b*0.04 = 240 + 0.03b
80 - 240 = 0.03b - b*0.04
-160 = -0.01b
b = 160/0.01
b = 16000

the panels from the plant b were 16000