Question

What is the temperature change on a 150g sample of mercury? (specific heat = 0.0330 calgºC), if 480 cal of heat is added to it?O 9.47 cO 380 C 0 96.9 CO 0.0103

Answer 1

The temperature change is 96.97°C.

Step-by-step explanation:

The given information from the exercise is:

- Mass (m): 150g

- Specific heat of mercury (c): 0.0330cal/g.°C

- Heat (q): 480cal

To calculate the temperature change (ΔT) it is necessary to use the Heat formula, and replace the values of mass, specific heat and heat:

`\begin{gathered} q=m*c*\Delta T \\ 480cal=150g*0.0330(cal)/(g*°C)*\Delta T \\ 480cal=4.95(cal)/(°C)*\Delta T \\ (480cal)/(4.95(cal)/(°C))=\Delta T \\ 96.97\degree C=\Delta T \end{gathered}`

So, the temperature change is 96.97°C.