Final answer:
To solve the system of equations 4x+3y=14 and 2y=6+4x, we can find the values of x and y that satisfy both equations. By solving for y in terms of x and substituting the expression back into one of the equations, we can find the values x = 0.5 and y = 1.
Step-by-step explanation:
Given the equations 4x+3y=14 and 2y=6+4x, we can solve for the values of x and y that satisfy both equations.
First, let's solve for y in terms of x using the second equation: 2y=6+4x. Divide both sides by 2 to get y = 3 + 2x.
Substitute this expression for y into the first equation: 4x + 3(3 + 2x) = 14. Simplify the expression to get 4x + 9 + 6x = 14. Combine like terms to get 10x + 9 = 14. Subtract 9 from both sides to get 10x = 5. Divide both sides by 10 to get x = 0.5.
Now, substitute the value of x back into either equation to solve for y: 2y = 6 + 4(0.5). Simplify to get 2y = 6 + 2. Subtract 6 from both sides to get 2y = 2. Finally, divide both sides by 2 to get y = 1.