Question

What are the units of k in the following expression: rate =k [A][B]?

Answer 1

moldm^_³*.moldm-³ =mol²dm^-6

Answer 2

Answer:
`mol^(-1)Ls^(-1)`

Step-by-step explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

`Rate=k[A]^x[B]^y`

k= rate constant

x = order with respect to A

y = order with respect to A

Given :
`Rate=k[A]^1[B]^1`

`k=(rate)/([A]^1[B]^1)`

Putting the units of various quantities:

`k=(rate)/([A]^1[B]^1)`

`k=(molL^(-1)s^(-1))/([molL^(-1)]^1[molL^(-1)]^1)`

`k=mol^(-1)Ls^(-1)`

Thus units of rate constant are
`mol^(-1)Ls^(-1)`