Question

A 90-kg tight end moving at 9.0 m/s encounters at 400 N•s impulse. Determine the velocity change of the tight end.

Answer 1

Δp=mΔv
400 N.s = (90kg) (vf-9m/s)
400 = 90 vf - 810
400 + 810 = 90 vf
1210 = 90vf
vf= 13.4 m/s

Answer 2

Answer: The change velocity of the tight end is 4.44 m/s

Step-by-step explanation:

Mass of the tight end = 90 kg

Initial velocity =
`u` = 9.0 m/s

Final velocity =
`v`

`Impulse=Force* Time`

`Impulse=Mass * acceleration* Time`

`a=(dv)/(dt)=([v-u])/(t)`

`impulse=Mass * [v-u]`

`400 Nm=90 kg*[v-9.0 m/s]`

`v=13.44 m/s`

Change in velocity = 13.44 m/s - 9m/s = 4.44 m/s

The change velocity of the tight end is 4.44 m/s