131k views
0 votes
What is the coefficient of x^2y^3 in the expansion of (2x+y)^5

2 Answers

5 votes
We figure out the coefficient of x^2y^3 by figuring out the coefficients in both (x+y)^4 and (x+2y)^4.

Using the binomial theorem, the coefficient of x^2y^3 on the first expansion is

(4 choose 3)x^2y^3=6x^2y^3,

and the coefficient of x^2y^3 on the second expansion is

(4 choose 3)x^2(2y)^3=6x^2(4y^2)=24x^2y^3.

Thus, the coefficient in the sum of these two expansions is 6+24=30.
User Sergey Ilinsky
by
8.5k points
6 votes

Answer:

40

Explanation:

A P E X

User Hunteros
by
8.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories