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What is the coefficient of x^2y^3 in the expansion of (2x+y)^5

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We figure out the coefficient of x^2y^3 by figuring out the coefficients in both (x+y)^4 and (x+2y)^4.

Using the binomial theorem, the coefficient of x^2y^3 on the first expansion is

(4 choose 3)x^2y^3=6x^2y^3,

and the coefficient of x^2y^3 on the second expansion is

(4 choose 3)x^2(2y)^3=6x^2(4y^2)=24x^2y^3.

Thus, the coefficient in the sum of these two expansions is 6+24=30.
User Sergey Ilinsky
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6 votes

Answer:

40

Explanation:

A P E X

User Hunteros
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7.9k points