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What is the Square root of 69?

User Hoan
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√(69)\ is\ irrational\ number\\\\69=3*23\\\\therefore\ √(69)=√(3*23)=\sqrt3*√(23)\\\\\sqrt3-not\ exist\ in\ the\ set\ of\ rational\ numbres\\and\\√(23)-not\ exist\ in\ the\ set\ of\ rational\ numbers\\\\You\ can\ only\ rounding\ this\ number:√(69)\approx8.307
User Maksimr
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