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Find the length of a rectangular lot with a perimeter of 126 meters if the length is 7 meters more than the width.

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Let, the width = x

length = x+7

Now, 2(x+7+x) = 126

2(2x+7)=126

4x+14 = 126

4x = 112

x = 28

So, length would be(x+7) = 28+7 = 35meters

User Nick Alexander
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