Question

A 10 kg mass on a horizontal friction free air track is accelerated by a string attached to another 10-kg mass hanging vertically from a pulley as shown.What is the force due to gravity in newtons of the hanging 10-kg mass? What is the acceleration of the system of both masses?

Answer 1

1 ) The force due to gravity:
F g = m * g = 10 kg * 9.81 m/s²
F g = 98.1 N
2 ) The system:
m 1 * a = m g - T
+
m 2 a = T
-----------------------
a * (m 1 + m 2) = m g
a * 20 kg = 98.1 N
a = 98.1 : 20
a = 4.905 m/s²

Answer 2

1. Answer;

Force = 98.1 Newtons

Step-by-step explanation;

-On the hanging mass the net force is

Fnet = Mh*g - T = Mh*a where Mh is the mass = 10kg, g = 9.81m/s², and T the tension in the string. Its acceleration is a ( same as g)

Thus; Force = 10 kg × 9.81 m/s²

= 98.1 Newtons.

2. Answer;

a = 4.905 m/s²

Solution;

-We know that that T = Ms*a, but Fnet = Mh*g - T = Mh*a

Substituting; T with Ms*a

Mh*g - Ms*a = Mh*a

Mh*a + Ms*a = Mh*g

a = Mh*g/(Mh + Ms)

= 10.0kg*9.81 m/s²/(10kg + 10kg)

= 4.905 m/s²