Question

A particular sound wave can be graphed using the function y = –3 sin x. Find the period of the function.

a. period = 2pi
b. period = –3
c. period = 3
d. period = 1/2

Answer 1

a) period = 2 pi.

Explanation:

Given : A particular sound wave can be graphed using the function y = –3 sin x.

To find :Find the period of the function.

Solution : We have given that y = –3 sin x.

By the sine function : =a sin (bx) .

Where, a = amplitude, b = any number ,

Formula of time period =
`(2\ pi)/(b)`

On comparing the sine function with given function

Here, a = -3 , b = 1

Plugging the values in formula of period

Then, Period =
`(2\ pi)/(1)`.

Period = 2 pi

Therefore, a) period = 2 pi.

Answer 2

f ( x ) 0 - 3 sin x
The period of the function:
T = 2 π / b
f ( x ) = a sin (bx)
In this case: b = 1.
Therefore: T = 2 π / 1 = 2π
Answer:
A ) Period = 2 π