Question

Light traveling through air at 3.00 · 10^8 m/s reaches an unknown medium and slows down to 2.00 · 10^8 m/s. What is the index of refraction of that medium? n =

Answer 1

The index of refraction of medium is 1.5 .

Step-by-step explanation:

Equation for index of refraction is given by .

`n = (c)/(v)`

Where n is index of refraction in medium , v is speed of light in the medium and c is the speed of light in air .

As given

Light traveling through air at
`3.00* 10^8` m/s reaches an unknown medium and slows down to
`3.00* 10^8` m/s.

`c = 3.00* 10^(8)`

`v = 2.00* 10^(8)`

Putting the values in the formula

`n = (3.00* 10^(8))/(2.00* 10^(8))`

Solving the above

n = 1.5

Therefore the index of refraction of medium is 1.5 .

Answer 2

v 1= 3.00 · 10^8 m/s
v 2 = 2.00 · 10^8 m/s
The index of refraction:
n = v 1 / v 2 = 3.00 · 10^8 m/s : 2.00 · 10^8 m/s = 1.5
Answer:
The index of refraction of that medium is 1.5