Question

How many moles of calcium chloride would be produced by the reaction below when 53.2 milliliters of water are produced, if the density of water is 0.987 g/mL? Show all steps of your calculations as well as the final answer HCl + Ca(OH) 2 → H2O + CaCl2

Answer 1

All the steps are bieng shown below :

`Ca(OH)2+ 2HCl → CaCl2 + 2H20`
Mass of water = .987 * 53.2 = 52.5084 g
Mole of water = 52.5084g/ 18= 2.917 mol
Mole of CaCl2= 2.917 mol / 2 = 1.458

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