Question

When [OH-] changes from 10-9 to 10-11 in a solution:

Kw = [H+][OH-]

What is the [H+] after the change?

Answer 1

2

Step-by-step explanation:

Answer 2

According to the fact that [H+]*[OH-] is always equal Kw
`= 1x10^(-14)`, you can easily find concentration of [H+] by changing from
`1*10^(-9)`to
`1*10^(-11)`
H increases, Kw is constant, therefore
`10^-14 / 10^-11 = 10^-3.`
And you will have
`Hence [H+] = 10^-3` where pH is 3