213k views
4 votes
Find the equation of the line that passes through (-1, 4) and is perpendicular to the

line that passes through (2, 2) and (4, - 4)
(A) y = 3x + 7
(B) y = - 1/3 x +1/3
(C) y=1/3x+13/3
(D) y =- 3x + 8
(E) none of these

User Dinah
by
7.4k points

1 Answer

2 votes
For perpendicular lines, m2 = -1/m1; where m1 is the slope of line 1 and m2 is the slope of line 2.
m1 = (-4 - 2)/(4 - 2) = -6/2 = -3
m2 = -1/-3 = 1/3
Equation of the required line is given by: y - 4 = 1/3 (x - (-1))
y - 4 = 1/3 x + 1/3
y = 1/3 x + 1/3 + 4
y = 1/3 x + 13/3
User Martineno
by
7.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories