Question

What is the equation in point-slope form of the line passing through (−2, 1) and (4, 13)? y − 1 = −2(x − 4) y − 1 = 2(x 2) y − 13 = −2(x 2) y − 13 = 2(x 4)

Answer 1

Equation of a line is given by y - y1 = m(x - x1); where m = (y2 - y1)/(x2 - x1) is the slope.
y - 1 = ((13 - 1)/(4 - (-2))(x - (-2))
y - 1 = (12/(4 + 2))(x + 2)
y - 1 = 12/6 (x + 2)
y - 1 = 2(x + 2)