Question

I need help with my math

Answer 1

Given

Equations

Procedure

`\begin{gathered} x-4y=8 \\ x-8=4y \\ y=(x-8)/(4) \\ y=(x)/(4)-(8)/(4) \\ y=(x)/(4)-2 \end{gathered}`

`\begin{gathered} 3y=4x-27 \\ y=(4x-27)/(3) \\ y=(4x)/(3)-(27)/(3) \\ y=(4)/(3)x-9 \end{gathered}`

`\begin{gathered} y+9=2(x+5) \\ y+9=2x+10 \\ y=2x+10-9 \\ y=2x+1 \end{gathered}`
`\begin{gathered} y-1=(2)/(3)(x+3) \\ y-1=(2)/(3)x+(2)/(3)3 \\ y-1=(2)/(3)x+2 \\ y=(2)/(3)x+2+1 \\ y=(2)/(3)x+3 \end{gathered}`