Question

The square and the triangle have equal perimeters find the value of x find the perimeter

Answer 1

To find the value of x in a square and triangle with equal perimeters, set up an equation and solve for x.

Step-by-step explanation:

To find the value of x in a square and triangle with equal perimeters, we need to set up an equation. Let's assume that the side length of the square is s and the base of the triangle is b. The perimeter of the square is 4s, and the perimeter of the triangle is s + b + 2x, where x is the height of the triangle. Since both perimeters are equal, we can set up the equation: 4s = s + b + 2x. From there, we can solve for x.

Answer 2

Answer: The required value of x is 10 and the perimeter is 28.

Step-by-step explanation: Given that the square and the triangle have equal perimeters.

We are to find the value of x and the perimeter.

From the given figure, we note that

length of a side of the square, a = x-3

and the lengths of the sides of the triangle are x, x and 8.

According to the given information, we get

`4a=x+x+8\\\\\Rightarrow 4(x-3)=2x+8\\\\\Rightarrow 4x-12=2x+8\\\\\Rightarrow 4x-2x=8+12\\\\\Rightarrow 2x=20\\\\\Rightarrow x=(20)/(2)\\\\\Rightarrow x=10.`

Also, the perimeter of the square and the triangle is

`4(x-3)=4(10-3)=4*7=28`

Thus, the required value of x is 10 and the perimeter is 28.