Question

A bag contains two kinds of fruit: orangesand pears. The probability of picking anorange is 0.2 and there are 3 oranges. Howmany pears are in the bag?

Answer 1

In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data:

bag:

oranges and pears

# oranges = 3

p (oranges) = 0.2

Step 02:

probability:

p (event) = favorable outcomes / total outcomes

Event = orages:

# pears = p

favorable outcomes =e3

total outcomes = (# oranges + #pears) = (3 + p)

`\begin{gathered} 0.2\text{ = }(3)/((3+p)) \\ \\ 0.2\text{ * \lparen3+p\rparen = 3 } \\ \\ 0.6\text{ + 0.2p = 3 } \end{gathered}`
`\begin{gathered} 0.2p\text{ = 3 - 0.6} \\ \\ p\text{ = }(2.4)/(0.2)=12 \end{gathered}`

The answer is:

There are 12 pears i the bag