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Harlene tosses two number cubes. If a sum of 8 or 12 comes up, she gets 9 points. If not, she loses 2 points. What is the expected value of the number of points for one roll?

Harlene tosses two number cubes. If a sum of 8 or 12 comes up, she gets 9 points. If not, she loses 2 points. What is the expected value of the number of points for one roll?
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Harlene tosses two number cubes. If a sum of 8 or 12 comes up, she gets 9 points. If not, she loses 2 points. What is the expected value of the number of points for one roll?

User Pierre Lapointe
by
8.5k points

2 Answers

1 vote

Answer:

-(1/6)

Explanation:

User RandomBytes
by
8.7k points
1 vote
P(8 or 12) = 1/6
P(not 8 or 12 = 5/6
Let the expected points fro one roll be X.

E(X)=9*(1)/(6)-2*(5)/(6)=-(1)/(6)\ points
The answer is -(1/6) points.
User Yacine Filali
by
8.2k points
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