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Find the 13th term of the binomial expansion of: (2x-4)^21 Please help :(

User GJZ
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T_r={n \choose r-1}a^(n-r+1)b^(r-1)\\ T_(13)={21 \choose 13-1}(2x)^(21-13+1)(-4)^(13-1)\\ T_(13)={21 \choose 12}(2x)^9(-4)^(12)\\ T_(13)=(21!)/(12!9!)\cdot512x^9\cdot16777216\\ T_(13)=293930\cdot8589934592x^9\\ T_(13)=2524839474626560x^9
User Illusionx
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