40.8k views
3 votes
If f(x) = 4 – x2 and g(x) = 6x, which expression is equivalent to (g –

f.(3)? 6 – 3 – (4 3)^2 6 – 3 – (4 – 3^2) 6(3) – 4 3^2 6(3) – 4 – 3^2

User Josh Russo
by
6.4k points

2 Answers

3 votes
f(x) = 4 - x^2
g(x) = 6x
(g - f)(x) = g(x) - f(x) = 6x - (4 - x^2) = 6x - 4 + x^2
(g - f)(3) = 6(3) - 4 + 3^2
User Zeroef
by
6.7k points
4 votes

Answer:

Option (c) is correct.


(g-f)(3)=6(3)-4+(3)^2

Explanation:

Given :
f(x)=4-x^2\\\\ g(x)=6x

We have to find the expression is equivalent to (g –f)(3)

That is g(3) - f(3)

First find g(x) - f(x)

We have,


g(x)-f(x)=6x-(4-x^2)\\\\ g(x)-f(x)=6x-4+x^2

Now, put x = 3

We have,


g(3)-f(3)=6(3)-4+(3)^2

Thus,
(g-f)(3)=6(3)-4+(3)^2

User Daniel Lin
by
6.7k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.