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What is the cube root of 8x27

User Mellort
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2 Answers

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I hope this helps you
What is the cube root of 8x27-example-1
User Asim Ihsan
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8.1k points
3 votes

Answer:


2* 3

Explanation:

We have been given an expression and we are asked to find the cube root of our given expression.


\sqrt[3]{8* 27}

Using the property for radicals
\sqrt[n]{a* b}=\sqrt[n]{a}* \sqrt[n]{b} we can rewrite our expression as:


\sqrt[3]{8}* \sqrt[3]{27}

We can rewrite terms of our given expression as:


8=2^3


27=3^3

Now, we will substitute back these terms back in our given expression.


\sqrt[3]{2^3}* \sqrt[3]{3^3}

Using exponent property
\sqrt[n]{x^m}=x^{(m)/(n)}, we can rewrite our expression as:


2^{(3)/(3)}* 3{(3)/(3)}


2^(1)* 3^(1)


2* 3

Therefore, the cube root of our given expression is
2* 3.

User Prabagaran
by
8.8k points

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