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What is the mass in grams of manganese in 0.412 g of Mn3O4

User Orfdorf
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.412 g Mn304/ 1mol * 1 mol Mn304/228.82(MM of Mn3O4 molecule)* 3 mol Mn/1 mol Mn3O4 = .00540 mol Mn *54.94 g/mol = .296 g Mn
User Anton Tananaev
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