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Mervin had some cartons of milk he sold 2/5 of the cartons of milk in the morning .he then sold 3/4 of the remainder in the afternoon .24 more cartons of milk were sold in the afternoon than in the morning ..how many cartons of milk did Mervin have at first

User Amsakanna
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2 Answers

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Final answer:

Mervin initially had 480 cartons of milk. He sold 2/5 in the morning and 3/4 of the remainder in the afternoon, with a difference of 24 more cartons sold in the afternoon compared to the morning.

Step-by-step explanation:

The question asks us to find the number of cartons of milk Mervin had initially. Mervin sold 2/5 of his cartons of milk in the morning and then 3/4 of the remainder in the afternoon, with 24 more cartons being sold in the afternoon than in the morning.

Let's assume Mervin started with x cartons of milk. In the morning, he sold 2/5 of them, so he had 3/5 of x cartons left. In the afternoon, he sold 3/4 of the remaining cartons. This means he had 1/4 of 3/5 of x cartons left, equating to 3/20 of x. Since he sold 24 more cartons in the afternoon than in the morning, we can set up the equation: (3/4) * (3/5 * x) - (2/5 * x) = 24.

To solve for x, simplify the equation: 9/20x - 8/20x = 24 which simplifies to 1/20x = 24. Multiplying both sides by 20 gives us x = 480. This means Mervin had 480 cartons of milk at first.

User Dorsh
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1 vote
I think it is 12. I think its 12 because 12 is half of 24. Otherwise, I'm new to this and I really have a question to ask so I need points...Sorry if I'm wrong!
User Glenn
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