Question

A plane is flying to Minnesota with a velocity of 434.21 km/h, N. The planeencounters a crosswind with a velocity of 93.07 km/h, W. What is the magnitude ofthe resultant velocity of the plane?

Answer 1

A plane is flying to Minnesota with a velocity of 434.21 km/h, North.

The plane encounters a crosswind with a velocity of 93.07 km/h, West.

We are asked to find the magnitude of the resultant velocity of the plane.

Let us draw a diagram to better understand the problem.

The magnitude of the resultant velocity of the plane is given by

`\begin{gathered} |v|=\sqrt[]{434.21^2+93.07^2} \\ |v|=\sqrt[]{188538.3241+8662.0249} \\ |v|=\sqrt[]{197200.349} \\ |v|=444.07\; \; (m)/(s) \end{gathered}`

Therefore, the magnitude of the resultant velocity of the plane is 444.07 m/s