Question

A car moved in positive x direction with an initial velocity of 5 m/s accelerated withuniform acceleration of 1.6 m/s2 to 26.82 m/s. What is the total distance travelled?

Answer 1

216.97 meters

Explanation:

From the newton's second law:

`s=((v^2-u^2))/(2a)`

where v is the final velocity, and the initial velocity and a at the acceleration, we replace:

`\begin{gathered} s=(26.82^2-5^2)/(2\cdot1.6) \\ s=216.97\text{ m} \end{gathered}`

The distance traveled is 216.97 meters