Question

Find the value of the sine, cosine,and tangent function for 0please I need help it's due at 10pm

Answer 1

`\begin{gathered} \sin \theta=\frac{\text{3}}{\sqrt[]{13}} \\ \cos \theta=\frac{\text{2}}{\sqrt[]{13}} \\ \tan \theta=\frac{\text{2}}{\text{3}} \end{gathered}`

Explanation:

We have the following trigonometric ratios

`\begin{gathered} \sin \theta=\frac{\text{opposite}}{\text{hypotenuse}} \\ \cos \theta=\frac{\text{adjacent}}{\text{hypotenuse}} \\ \tan \theta=\frac{\text{opposite}}{\text{adjacent}} \\ \text{opposite}=3 \\ \text{adjacent}=2 \\ \text{hypotenuse =}\sqrt[]{13} \end{gathered}`

replacing:

`\begin{gathered} \sin \theta=\frac{\text{3}}{\sqrt[]{13}} \\ \cos \theta=\frac{\text{2}}{\sqrt[]{13}} \\ \tan \theta=\frac{\text{2}}{\text{3}} \end{gathered}`