Question

It takes 40 oz of grass to seed 3200 square ft of lawn. At this , how much would be needed for 8800 square ft of lawn

Answer 1

To find how many lots of grass seed we need, divide 8800 by 3200.
8800 / 3200 = 2.75
Then, simply multiply this number by the number of ounces in one lot of grass seed.
2.75 x 40 = 110
110 oz of grass seed are needed for 8800 square feet of lawn.