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A bullet with mass 50.0 g is fired with an initial velocity of 625 m/s from a gun with a mass 3.50 kg. What is the speed of recoil (in m/s) of the gun?

User Otaku
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1 Answer

3 votes

m1v1 = m2v2

0.05*625 = 3.50 * v2

v2 = 31.25/3.50

v2=8.92m/s

User Joebalt
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