Question

Please calculate the energy stored in a flying wheel. The steel flying wheel is 10 metric tons, in adiameter of 10m, and it rotates at a speed of 1000 rpm. The steel density is 8050 kg/m^3. When energyis fully released, the flying wheel stops its rotation.

Answer 1

685.38 MJ

Step-by-step explanation:

Given that:

mass = 10 tons = 1.0 × 10 ⁴ kg

diameter D = 10 m

radius R = 5 m

speed N = 1000 rpm

Using the formula for K.E =
`(1)/(2)I \omega^2` to calculate the energy stored

where;

`= (2 \pi * N)/(60)`

`= (2 \pi * 1000)/(60)`

= 104.719 rad/s

Hence, the energy stored is;

`= (1)/(2)* ((MR^2)/(2)) * \omega^2`

`= (1)/(2)* ((10^4* 5^2)/(2)) * 104.719^2`

= 685379310.1

= 685.38 MJ