Solve for x. what is 1900=1300(1+.0625)^x?

asked Feb 10, 2017 20.1k views

5 votes

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4 votes

1900 = 1300(1 + 0.0625)ˣ
1900 = 1300(1.0625)ˣ
1300 1300
1⁶/₁₃ = (1.0625)ˣ
㏑(1⁶/₁₃) = ln((1.0625)ˣ)
㏑(1⁶/₁₃) = x㏑(1¹/₁₆)
ln(1¹/₁₆) ln(1¹/₁₆)
6.26 ≈ x

DragonYen answered Feb 13, 2017

7.8k points

3 votes

First rearrange as:

(1900)/(1300)=1.0625^(x)

Taking logs of both sides, we get:

$log\ (1900)/(1300)=x\ log1.0625$

$x=(log(1900)/(1300))/(log\ 1.0625)=6.26$
x = 6.26.

Jagruti answered Feb 15, 2017

9.0k points

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