Question

You have a distribution summarizing the number of days in the past two months (60 days) that an individual watched TV. The median number of days = 25, the lower quartile = 21, and upper quartile = 42. Given this information, which of the following statements are true?

A. There are no outliers in this distribution.
B. The threshold value for the upper outlier is 31.5.
C. This distribution is skewed to the left.
D. The lower outlier threshold value is 10.
E. This distribution is roughly normally distributed.

Answer 1

Answer: A, there are no outliers in this distribution.

Explanation: the threshold values are equivalent to the lower quartile -(1.5 * IQR) and the upper quartile +(1.5 * IQR). Thus, (I.5 * IQR = 31.5), and the threshold values would equal (21 - 31.5 = -10.5) and (42 + 31.5 = 73.5). Since this is a 2 month span, the minimum days would be 0, and the maximum is 60. Therefore, it isn't possible to have outliers in this equation.

Answer 2

C. This distribution is skewed to the left.