Question

How many grams of Cl are in 325 g of CaCl2

Answer 1

207.63

Find the molar mass of the compound and divide 325 by that molar mass to get moles. Then use the mole to mole to convert moles of that compound to Cl. Then, multiply the moles of Cl by its molar mass on the periodic table 35.45.

Answer 2

Step-by-step explanation:

It is given that mass of chlorine is 325 g and molar mass of
`CaCl_(2)` is 110.98 g/mol.

Hence, calculate the number of moles as follows.

No. of moles =
`\frac{mass}{\text{molar mass}}`

=
`(325 g)/(110.98 g/mol)`

= 2.92 mol

As there are two chlorine atoms present in
`CaCl_(2)`. Hence, number of moles present in 2 chlorine atoms will be as follows.

`2 * 2.92`

= 5.85 mol

Therefore, mass of chlorine present in 5.85 mol of
`CaCl_(2)` will be as follows.

No. of moles =
`\frac{mass}{\text{molar mass}}`

5.85 mol =
`(mass)/(110.98 g/mol)`

mass = 649.23 g

Therefore, we can conclude that 649.23 g of Cl are present in given
`CaCl_(2)` compound.