2x + 3y = 12
I am going to put this in y = mx + b form, where m is ur slope and b is ur y intercept.
2x + 3y = 12
3y = -2x + 12
y = -2/3x + 4......slope is -2/3 and y int is (0,4)
x int can be found by subbing in 0 for y and solving for x
2x + 3y = 12
2x + 3(0) = 12
2x = 12
x = 6.....so x int is (6,0)
start at y int (0,4).....and since the slope is -2/3, come down 2 spaces, and to the right 3 spaces, then down 2 spaces, to the right 3 spaces....keep doing that and u should cross the x axis at (6,0)