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How many moles of bromine (Br) atoms are in a sample of 2.03 × 1024 atoms?

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The mole is simply an Avogadros number of anything( in this case Br atoms)

The Avogadro number is 6.022 x 10^23.

So no of moles = No of atoms / 6.022 x 10^23 = 2.03 x 10^24 / 6.022 x 10^23 = 3.37 Moles.
User Sublimemm
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Answer: The number of moles of bromine atoms in the given amount of sample is 3.37 moles.

Step-by-step explanation:

According to mole concept:

1 mole of an element contains
6.022]times 10^(23) number of atoms

We are given:

Number of bromine atoms =
2.03* 10^(24)

As,
6.022]times 10^(23) atoms form 1 mole of an element.

So,
2.03* 10^(24) atoms will form =
(1)/(6.022* 10^(23))* 2.03* 10^(24)=3.37moles of bromine element.

Hence, the number of moles of bromine atoms in the given amount of sample is 3.37 moles.

User Jens Lundstrom
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