Question

If I dilute 334.75 mL of 1.28 M lithium acetate solution to a volume of 822.18 ml, what

will the concentration of this solution be?

Answer 1

C₂ = 0.52 M

Step-by-step explanation:

Given data:

Initial volume = 334.75 mL

Initial concentration = 1.28 M

Final volume = 822.18 mL

Final concentration = ?

Solution:

C₁V ₁ = C₂V₂

By putting values,

1.28 M×334.75 mL = C₂×822.18 mL

C₂ = 1.28 M×334.75 mL / 822.18 mL

C₂ = 428.48 M.mL / 822.18 mL

C₂ = 0.52 M