492,542 views
6 votes
6 votes
2 A point inside rectangle RECT, shownbelow, is chosen at random.30 cm22 cm15 cm15 cmTWhat is the probability that the pointis in the shaded region?

2 A point inside rectangle RECT, shownbelow, is chosen at random.30 cm22 cm15 cm15 cmTWhat-example-1
User Friction
by
2.8k points

1 Answer

16 votes
16 votes

Answer

Probability that a randomly chosen point lies in the shaded region = 0.66

Step-by-step explanation

The probability of an event is calculated as the number of elements in the event divided by the total number of elements in the sample space.

For this question,

Area of the shaded region

= (Area of the whole rectangle) - (Area of the unshaded rectangle)

Area of a rectangle = Length × Width

Area of the shaded region

= (Area of the whole rectangle) - (Area of the unshaded rectangle)

= (30 × 22) - (15 × 15)

= 660 - 225

= 435 cm²

Area of the whole rectangle = 30 × 22 = 660 cm²

Probability that a randomly chosen point lies in the shaded region = (435/660) = 0.659

Hope this Helps!!!

User Randrumree
by
3.0k points