Question

find two consecutive integers such that ten more than twice the smaller is seven less than three times the larger.

Answer 1

one integer should be x
and the second one should be x+1
according to the question
2x+10 = 3(x+1) - 7
2x+10 = 3x+3-7
2x +10 = 3x-4
2x-3x+10+4 = 0
-x + 14= 0
-x = -14
minus got canceled out
therefore,
x = 14 and
x+1
14+ 1
15
so the numbers are 14 and 15